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#14 Brain Teaser: Party For Polyglots

April 9, 2007 by Caroline Latham

We are delight­ed to intro­duce you to Wes Car­roll who has gra­cious­ly cre­at­ed a few new puz­zles to bend all those sharp brains out there! Wes Carroll

Wes is the head of Do The Math pri­vate tutor­ing ser­vices, Puz­zle Mas­ter for the Ask A Sci­en­tist lec­ture series, and an inter­na­tion­al­ly tour­ing per­former and teacher of music. With no fur­ther ado, the first puzzle!

Par­ty For Polyglots

Dif­fi­cul­ty: MEDIUM
Type: LOGIC

QUESTION:
Of the 100 peo­ple at a recent par­ty, 90 spoke Span­ish, 80 spoke Ital­ian, and 75 spoke Man­darin. At least how many spoke all three languages?

Have you solved it yet? If you are work­ing the prob­lem, mak­ing hypothe­ses, test­ing your ideas, and com­ing up with a solu­tion, you are using your frontal lobes. This is great exer­cise because the frontal lobes fol­low the “last hired, first fired” adage. They are they last areas of your brain to devel­op and the first to suf­fer the rav­ages of time and stress. So, keep exer­cis­ing them!

ANSWER:
45

EXPLANATION:
10 could not speak Span­ish, 20 could not speak Ital­ian, and 25 could not speak Man­darin. So there could have been 10 peo­ple who spoke none of those languages.

How­ev­er, that would max­i­mize the num­ber of peo­ple who could speak all three, and the prob­lem asks at least how many speak all three. There­fore, we must assume that these 10, 20, and 25 peo­ple are all sep­a­rate peo­ple. Hav­ing iden­ti­fied 55 each of whom is miss­ing one lan­guage, the remain­ing 45 speak all three.

Next brain teas­er in Sharp­Brains’ top 25 series:

  • #15. Fun & Brainy Haikus. Yours?

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Filed Under: Brain Teasers Tagged With: assess-driving-fitness, Brain Teasers, Clinical-Trial, maintain-independence, memory-techniques, mental-quickness, Neural-Wreckage, OLLI, processing-speed-cognitive-abilities, SFSU, tony-robbins, UCSF

Reader Interactions

Comments

  1. Caroline says

    April 19, 2007 at 10:55

    If you liked this puz­zle, you can try a few more by oth­er puz­zlers at The Car­ni­val of Math­e­mat­ics. Enjoy!

  2. The Science Pundit says

    April 21, 2007 at 6:25

    I like it. I actu­al­ly solved it from the oppo­site direc­tion: I start­ed with the speak­ers of one lan­guage and subtracted.

  3. Caroline says

    April 21, 2007 at 6:41

    Glad you liked it, and cre­ative solu­tions are always encouraged!

  4. pjsk8 says

    October 18, 2007 at 10:04

    At least ONE per­son can speak all three languages.

  5. Beck says

    November 7, 2007 at 10:59

    Used same method as The Sci­ence Pundit.

    Pop­u­la­tion = 100
    With­in the population,
    Span­ish Speak­ers = 90
    Ital­ian Speak­ers = 80
    Man­darin Speak­ers = 75

    So, for the min­i­mum num­ber of all three lan­guage speak­ers or total overlap…

    x = 90 — (100 — 80) — (100 — 75)

  6. k says

    November 28, 2007 at 4:05

    9/10 x 8/10 x 3/4 = 216/400 => 54 People

  7. scott says

    December 17, 2007 at 9:26

    90+80+75=245 language/people

    245–200=45

    there were 45 more language/people than if 2 lan­guages were spo­ken by all 100 people.

  8. BJ says

    September 29, 2008 at 12:16

    I chal­lenge some­one to cre­ate a Venn dia­gram with 45 peo­ple for 3 lan­guages and have the var­i­ous totals add up correctly

  9. Eric says

    November 13, 2008 at 4:31

    For the Venn dia­gram: 25 speak Ital­ian and Span­ish, 20 speak
    Man­darin and Span­ish, and 10 speak Man­darin and Italian.

  10. allstar says

    December 24, 2008 at 8:14

    i remem­ber doing this exact same ques­tion in maths at school. final­ly got it, took me a while to remem­ber how 🙂
    10 don’t speak spanish
    25 don’t speak mandarin
    20 don’t speak italian
    there­fore the rest speak all lan­guages — 45 … if that makes sense

  11. ddd69 says

    February 2, 2009 at 3:54

    10 cant speak spanish
    20 cant speak italian
    25 cant speak mandarin
    so
    100 — (10+20+25)= 45
    can speak 3 languages

  12. michelle says

    October 22, 2009 at 1:46

    pjsk8 is right. I don’t think the writer intend­ed it, but the way the ques­tion was phrased, it is ask­ing for the min­i­mum of speak­ers that can speak all three lan­guages. That being 1. 

    the work “atleast” is key.

  13. Abhishek says

    November 7, 2009 at 2:46

    10 peo­ples can­not speak span­ish, 20 peo­ple can­not speak Ital­ian and 25 can­not speak man­drin. Adding all of them comes 55. So there are 55 peo­ple who can­not speak alteast one lan­guage. Remain­ing 45 peo­ple can speak all the three lan­guages. It is log­i­cal­ly very good puz­zle!!! Thanks for such stuff

  14. abhishek says

    November 9, 2009 at 2:13

    prob­lem can be solved by two method…the log­i­cal way give us 45..but per­son who do lat­er­al think­ing kind of puz­zle must reply 1..

  15. Brad Donner says

    June 27, 2017 at 3:13

    A min­i­mum of ten could not speak all three lan­guages; and a max­i­mum of 75 could, all con­sid­ered with­out assumptions.

  16. Brad Donner says

    June 27, 2017 at 3:29

    I stand cor­rect­ed. A min­i­mum of 25 could not speak all three, and a max­i­mum of 75 could; allow­ing that some only speak one or two languages.

  17. Javier says

    September 13, 2017 at 11:16

    i have a ques­tion about this riddle.
    the rid­dle is pro­posed as if there are exact­ly 100 of peo­ple at the party.
    So, if you think so, this prob­lem maybe be equal to a prob­a­bil­i­ty prob­lem to find the num­ber of pos­si­bil­i­ties to find a per­son between 100 who speaks Span­ish, Ital­ian and Chi­nese lan­guage. If you applies prob­a­bil­i­ty the­o­ry to find event P(S ? I ? M) (S: Span­ish) (I: Ital­ian) (M: Man­darin) of a per­son that speaks these lan­guages. So, if you mul­tip­plies the prob­a­bil­i­ties of speak Span­ish, Ital­ian and Man­darin the answer is 54.
    I imag­ine that there was a mis­take of my part but if some­one could help me, I will thank very much.

    • Javier says

      September 13, 2017 at 3:16

      Per­haps 54 is the max­i­mum val­ue and 45 the min­i­mum value.

      • Javier says

        September 13, 2017 at 3:51

        xd obvi­ous­ly not cause max­i­mum val­ue is 75 of peo­ple that speak three languages.
        My head will explode

  18. Satyaraja Dasara says

    May 29, 2020 at 8:09

    The main thing here is to find the trilinguals.
    Those who can’t speak a lan­guage can speak atleast one of oth­er two languages.
    But we strict­ly need trilinguals.
    So those who don’t speak the lan­guage are summed up as non trilinguals.
    So Total — Sum of non trilin­guals = Pos­si­ble Trilinguals

    Btw I think the ques­tion should be atmost trilin­guals not atleast.

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